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On the recursive sequence xn+1=xn−(4k+3)1+∏t=02xn−(k+1)t−k

Dağıstan ŞİMŞEK | Fahreddin ABDULLAYEV

The solution of the difference equation (Formula presented.),..., where x−(4k+3), x−(4k+2),..., x−1, x0 ∈ (0, ∞) and k = 0, 1,..., is studied.

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On the Recursive Sequence xn+1=xn−(k+1)1+xnxn−1…xn−k

Dağıstan ŞİMŞEK

A solution of the following difference equation is investigated:xn+1=xn−(k+1)1+xnxn−1…xn−k,n=0,1,2,… where x−(k+1); x−k; : : : ; x−1; x0 𝜖 (0;∞) and k = 0; 1; 2; : : :.

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