The solution of the difference equation (Formula presented.),..., where x−(4k+3), x−(4k+2),..., x−1, x0 ∈ (0, ∞) and k = 0, 1,..., is studied.
A solution of the following difference equation is investigated:xn+1=xn−(k+1)1+xnxn−1…xn−k,n=0,1,2,… where x−(k+1); x−k; : : : ; x−1; x0 𝜖 (0;∞) and k = 0; 1; 2; : : :.